11-3

**Naming Ionic Compounds** **<---Previous Assignment - Next Unit--->media type="custom" key="11496758"**


 * __Time Length__ **
 * not sure
 * __Instructions__ **
 * // Write the names of the compounds below. Use the spellings below to help. Use[[file:Polyatomic Ions Chart.docx]]on the second part. //
 * // Nitrogen = Nitride; Sulfur = Sulfide; Oxygen = Oxide; Chlorine = Chloride; Fluorine = Fluoride; Selenium = Selenide; Bromine = Bromide; Iodine = Iodide; Phosphorus = Phosphide //

__**Worksheet**__
 * // Write the name of the first one, then the second, but follow the rules below. //
 * // Change endings of Representative Ions to "ide" //
 * // Determine the charge of Transition Ions and use roman numerals to identify it. Example below. //

Iron (Fe) is a transition element. Therefore we do not know its charge. Phosphorus is a Representative Ion. Therefore, because of its group we know it has a -3 charge. There are 2 Phosphoruses,so if we multiply the charge (3) times how many there are (2) that gives us a total charge of 6 on the right side. (the sign doesnt really matter.) The right side charge and the left side charge balance out so we start with a total charge of 6 on the left. Divide that by the number of Irons (3). That gives us a charge for each iron of 2. Thus we know that the name of the Iron is Iron (II). ||
 * [[image:Finding_Charge_of_a_Transition_Ion.JPG width="323" height="225"]] || __**Explanation for naming Transition Metals.**__